56=-16t^2+24t+160

Solution for 56=-16t^2+24t+160 equation:

56=-16t^2+24t+160

We move all terms to the left:

56-(-16t^2+24t+160)=0

We get rid of parentheses

16t^2-24t-160+56=0

We add all the numbers together, and all the variables

16t^2-24t-104=0

a = 16; b = -24; c = -104;
Δ = b2-4ac
Δ = -242-4·16·(-104)
Δ = 7232
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{7232}=\sqrt{64*113}=\sqrt{64}*\sqrt{113}=8\sqrt{113}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-8\sqrt{113}}{2*16}=\frac{24-8\sqrt{113}}{32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+8\sqrt{113}}{2*16}=\frac{24+8\sqrt{113}}{32}
$